Base | Representation |
---|---|
bin | 10011101010011011… |
… | …101101000001101010 |
3 | 2000111101211112021112 |
4 | 103222123231001222 |
5 | 321214412000132 |
6 | 13411004510322 |
7 | 1345125352661 |
oct | 235233550152 |
9 | 60441745245 |
10 | 21113000042 |
11 | 8a54813472 |
12 | 411284b3a2 |
13 | 1cb615a844 |
14 | 1044049dd8 |
15 | 83881dab2 |
hex | 4ea6ed06a |
21113000042 has 4 divisors (see below), whose sum is σ = 31669500066. Its totient is φ = 10556500020.
The previous prime is 21113000039. The next prime is 21113000071. The reversal of 21113000042 is 24000031112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12982551481 + 8130448561 = 113941^2 + 90169^2 .
It is a junction number, because it is equal to n+sod(n) for n = 21112999990 and 21113000026.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5278250009 + ... + 5278250012.
Almost surely, 221113000042 is an apocalyptic number.
21113000042 is a deficient number, since it is larger than the sum of its proper divisors (10556500024).
21113000042 is a wasteful number, since it uses less digits than its factorization.
21113000042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10556500023.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 21113000042 its reverse (24000031112), we get a palindrome (45113031154).
The spelling of 21113000042 in words is "twenty-one billion, one hundred thirteen million, forty-two", and thus it is an aban number.
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