Base | Representation |
---|---|
bin | 10011101010011011… |
… | …101101000010000111 |
3 | 2000111101211112022121 |
4 | 103222123231002013 |
5 | 321214412000241 |
6 | 13411004510411 |
7 | 1345125353032 |
oct | 235233550207 |
9 | 60441745277 |
10 | 21113000071 |
11 | 8a54813499 |
12 | 411284b407 |
13 | 1cb615a867 |
14 | 104404a019 |
15 | 83881dad1 |
hex | 4ea6ed087 |
21113000071 has 2 divisors, whose sum is σ = 21113000072. Its totient is φ = 21113000070.
The previous prime is 21113000039. The next prime is 21113000087. The reversal of 21113000071 is 17000031112.
It is an a-pointer prime, because the next prime (21113000087) can be obtained adding 21113000071 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21113000071 - 25 = 21113000039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21113001071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556500035 + 10556500036.
It is an arithmetic number, because the mean of its divisors is an integer number (10556500036).
Almost surely, 221113000071 is an apocalyptic number.
21113000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113000071 is an equidigital number, since it uses as much as digits as its factorization.
21113000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 16.
Adding to 21113000071 its reverse (17000031112), we get a palindrome (38113031183).
The spelling of 21113000071 in words is "twenty-one billion, one hundred thirteen million, seventy-one", and thus it is an aban number.
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