Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1000101101110001011 |
3 | 202011222000101000020111 |
4 | 3010220111011232023 |
5 | 11424343240431403 |
6 | 240554120535151 |
7 | 21152666341114 |
oct | 3045025055613 |
9 | 664860330214 |
10 | 211130014603 |
11 | 815a3430982 |
12 | 34b030214b7 |
13 | 16ba9168b31 |
14 | a30c35720b |
15 | 575a64656d |
hex | 3128545b8b |
211130014603 has 2 divisors, whose sum is σ = 211130014604. Its totient is φ = 211130014602.
The previous prime is 211130014559. The next prime is 211130014609. The reversal of 211130014603 is 306410031112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211130014603 - 237 = 73691061131 is a prime.
It is not a weakly prime, because it can be changed into another prime (211130014609) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565007301 + 105565007302.
It is an arithmetic number, because the mean of its divisors is an integer number (105565007302).
Almost surely, 2211130014603 is an apocalyptic number.
211130014603 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130014603 is an equidigital number, since it uses as much as digits as its factorization.
211130014603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 211130014603 its reverse (306410031112), we get a palindrome (517540045715).
The spelling of 211130014603 in words is "two hundred eleven billion, one hundred thirty million, fourteen thousand, six hundred three".
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