Base | Representation |
---|---|
bin | 10011101010011011… |
… | …110000010010011011 |
3 | 2000111101212012121101 |
4 | 103222123300102123 |
5 | 321214412412103 |
6 | 13411005052231 |
7 | 1345125436636 |
oct | 235233602233 |
9 | 60441765541 |
10 | 21113013403 |
11 | 8a54822509 |
12 | 4112857077 |
13 | 1cb6163951 |
14 | 1044050c1d |
15 | 838822a1d |
hex | 4ea6f049b |
21113013403 has 2 divisors, whose sum is σ = 21113013404. Its totient is φ = 21113013402.
The previous prime is 21113013377. The next prime is 21113013413. The reversal of 21113013403 is 30431031112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21113013403 is a prime.
It is not a weakly prime, because it can be changed into another prime (21113013413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556506701 + 10556506702.
It is an arithmetic number, because the mean of its divisors is an integer number (10556506702).
Almost surely, 221113013403 is an apocalyptic number.
21113013403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113013403 is an equidigital number, since it uses as much as digits as its factorization.
21113013403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 21113013403 its reverse (30431031112), we get a palindrome (51544044515).
The spelling of 21113013403 in words is "twenty-one billion, one hundred thirteen million, thirteen thousand, four hundred three".
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