Base | Representation |
---|---|
bin | 1100010010100001010… |
… | …1100110001000011001 |
3 | 202011222000121202100011 |
4 | 3010220111212020121 |
5 | 11424343304203403 |
6 | 240554123441521 |
7 | 21153000433126 |
oct | 3045025461031 |
9 | 664860552304 |
10 | 211130147353 |
11 | 815a3511694 |
12 | 34b030862a1 |
13 | 16ba91b4398 |
14 | a30c38d74d |
15 | 575a670a6d |
hex | 3128566219 |
211130147353 has 2 divisors, whose sum is σ = 211130147354. Its totient is φ = 211130147352.
The previous prime is 211130147339. The next prime is 211130147357. The reversal of 211130147353 is 353741031112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106770137049 + 104360010304 = 326757^2 + 323048^2 .
It is a cyclic number.
It is not a de Polignac number, because 211130147353 - 29 = 211130146841 is a prime.
It is not a weakly prime, because it can be changed into another prime (211130147357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565073676 + 105565073677.
It is an arithmetic number, because the mean of its divisors is an integer number (105565073677).
Almost surely, 2211130147353 is an apocalyptic number.
It is an amenable number.
211130147353 is a deficient number, since it is larger than the sum of its proper divisors (1).
211130147353 is an equidigital number, since it uses as much as digits as its factorization.
211130147353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 211130147353 its reverse (353741031112), we get a palindrome (564871178465).
The spelling of 211130147353 in words is "two hundred eleven billion, one hundred thirty million, one hundred forty-seven thousand, three hundred fifty-three".
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