Base | Representation |
---|---|
bin | 1100010010100001100… |
… | …0111110011000101011 |
3 | 202011222002021202101202 |
4 | 3010220120332120223 |
5 | 11424344021030011 |
6 | 240554154434415 |
7 | 21153011112434 |
oct | 3045030763053 |
9 | 664862252352 |
10 | 211131033131 |
11 | 815a3a67137 |
12 | 34b03432a0b |
13 | 16ba9434605 |
14 | a30c54048b |
15 | 575a79823b |
hex | 312863e62b |
211131033131 has 2 divisors, whose sum is σ = 211131033132. Its totient is φ = 211131033130.
The previous prime is 211131033119. The next prime is 211131033203. The reversal of 211131033131 is 131330131112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211131033131 - 26 = 211131033067 is a prime.
It is a super-2 number, since 2×2111310331312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211131033731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105565516565 + 105565516566.
It is an arithmetic number, because the mean of its divisors is an integer number (105565516566).
Almost surely, 2211131033131 is an apocalyptic number.
211131033131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211131033131 is an equidigital number, since it uses as much as digits as its factorization.
211131033131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 211131033131 its reverse (131330131112), we get a palindrome (342461164243).
The spelling of 211131033131 in words is "two hundred eleven billion, one hundred thirty-one million, thirty-three thousand, one hundred thirty-one".
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