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2111312140021 = 7386997793897
BaseRepresentation
bin11110101110010100000…
…000101001011011110101
321110211122222021110001201
4132232110000221123311
5234042431401440041
64253531242252501
7305352166040440
oct36562400513365
97424588243051
102111312140021
11744447730137
122a122a1b7131
13124132859b96
147428c034657
1539dc03b2631
hex1eb940296f5

2111312140021 has 8 divisors (see below), whose sum is σ = 2412990820800. Its totient is φ = 1809649124448.

The previous prime is 2111312139997. The next prime is 2111312140057. The reversal of 2111312140021 is 1200412131112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111312140021 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2111312140121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3626056 + ... + 4167841.

It is an arithmetic number, because the mean of its divisors is an integer number (301623852600).

Almost surely, 22111312140021 is an apocalyptic number.

It is an amenable number.

2111312140021 is a deficient number, since it is larger than the sum of its proper divisors (301678680779).

2111312140021 is an equidigital number, since it uses as much as digits as its factorization.

2111312140021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7832603.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 2111312140021 its reverse (1200412131112), we get a palindrome (3311724271133).

The spelling of 2111312140021 in words is "two trillion, one hundred eleven billion, three hundred twelve million, one hundred forty thousand, twenty-one".

Divisors: 1 7 38699 270893 7793897 54557279 301616020003 2111312140021