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2111319075433 is a prime number
BaseRepresentation
bin11110101110010100011…
…011000110101001101001
321110211200110022210122211
4132232110123012221221
5234042440140403213
64253532051045121
7305352312014341
oct36562433065151
97424613283584
102111319075433
11744450637887
122a12305a07a1
13124134117889
147428cd1bd21
1539dc0cd253d
hex1eb946c6a69

2111319075433 has 2 divisors, whose sum is σ = 2111319075434. Its totient is φ = 2111319075432.

The previous prime is 2111319075409. The next prime is 2111319075451. The reversal of 2111319075433 is 3345709131112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1879344875664 + 231974199769 = 1370892^2 + 481637^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111319075433 is a prime.

It is not a weakly prime, because it can be changed into another prime (2111319075403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055659537716 + 1055659537717.

It is an arithmetic number, because the mean of its divisors is an integer number (1055659537717).

Almost surely, 22111319075433 is an apocalyptic number.

It is an amenable number.

2111319075433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111319075433 is an equidigital number, since it uses as much as digits as its factorization.

2111319075433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 40.

The spelling of 2111319075433 in words is "two trillion, one hundred eleven billion, three hundred nineteen million, seventy-five thousand, four hundred thirty-three".