Base | Representation |
---|---|
bin | 10011101010011100… |
… | …101011000111011001 |
3 | 2000111102022110010202 |
4 | 103222130223013121 |
5 | 321214443114421 |
6 | 13411014151545 |
7 | 1345130462303 |
oct | 235234530731 |
9 | 60442273122 |
10 | 21113254361 |
11 | 8a54977551 |
12 | 41129525b5 |
13 | 1cb6219524 |
14 | 10440b4973 |
15 | 83886e10b |
hex | 4ea72b1d9 |
21113254361 has 2 divisors, whose sum is σ = 21113254362. Its totient is φ = 21113254360.
The previous prime is 21113254291. The next prime is 21113254381. The reversal of 21113254361 is 16345231112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19378032025 + 1735222336 = 139205^2 + 41656^2 .
It is a cyclic number.
It is not a de Polignac number, because 21113254361 - 222 = 21109060057 is a prime.
It is not a weakly prime, because it can be changed into another prime (21113254381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10556627180 + 10556627181.
It is an arithmetic number, because the mean of its divisors is an integer number (10556627181).
Almost surely, 221113254361 is an apocalyptic number.
It is an amenable number.
21113254361 is a deficient number, since it is larger than the sum of its proper divisors (1).
21113254361 is an equidigital number, since it uses as much as digits as its factorization.
21113254361 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4320, while the sum is 29.
Adding to 21113254361 its reverse (16345231112), we get a palindrome (37458485473).
The spelling of 21113254361 in words is "twenty-one billion, one hundred thirteen million, two hundred fifty-four thousand, three hundred sixty-one".
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