Base | Representation |
---|---|
bin | 11110101110010101001… |
… | …101101010111001110011 |
3 | 21110211201101021021001022 |
4 | 132232111031222321303 |
5 | 234043002034043443 |
6 | 4253533243130055 |
7 | 305352532463561 |
oct | 36562515527163 |
9 | 7424641237038 |
10 | 2111332331123 |
11 | 744458070aa4 |
12 | 2a1234b1392b |
13 | 124136aa9292 |
14 | 742909aca31 |
15 | 39dc204ee68 |
hex | 1eb9536ae73 |
2111332331123 has 2 divisors, whose sum is σ = 2111332331124. Its totient is φ = 2111332331122.
The previous prime is 2111332331099. The next prime is 2111332331137. The reversal of 2111332331123 is 3211332331112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111332331123 - 216 = 2111332265587 is a prime.
It is a super-2 number, since 2×21113323311232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111332331092 and 2111332331101.
It is not a weakly prime, because it can be changed into another prime (2111332301123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055666165561 + 1055666165562.
It is an arithmetic number, because the mean of its divisors is an integer number (1055666165562).
Almost surely, 22111332331123 is an apocalyptic number.
2111332331123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111332331123 is an equidigital number, since it uses as much as digits as its factorization.
2111332331123 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 26.
Adding to 2111332331123 its reverse (3211332331112), we get a palindrome (5322664662235).
The spelling of 2111332331123 in words is "two trillion, one hundred eleven billion, three hundred thirty-two million, three hundred thirty-one thousand, one hundred twenty-three".
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