Base | Representation |
---|---|
bin | 11001001010110… |
… | …10011101100011 |
3 | 112201021201211011 |
4 | 30211122131203 |
5 | 413022244212 |
6 | 32541201351 |
7 | 5142416626 |
oct | 1445323543 |
9 | 481251734 |
10 | 211134307 |
11 | a91a836a |
12 | 5a860257 |
13 | 34985257 |
14 | 2007ddbd |
15 | 138084a7 |
hex | c95a763 |
211134307 has 2 divisors, whose sum is σ = 211134308. Its totient is φ = 211134306.
The previous prime is 211134299. The next prime is 211134311. The reversal of 211134307 is 703431112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211134307 - 23 = 211134299 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (211134317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105567153 + 105567154.
It is an arithmetic number, because the mean of its divisors is an integer number (105567154).
Almost surely, 2211134307 is an apocalyptic number.
211134307 is a deficient number, since it is larger than the sum of its proper divisors (1).
211134307 is an equidigital number, since it uses as much as digits as its factorization.
211134307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 22.
The square root of 211134307 is about 14530.4613484913. The cubic root of 211134307 is about 595.4604697639.
Adding to 211134307 its reverse (703431112), we get a palindrome (914565419).
The spelling of 211134307 in words is "two hundred eleven million, one hundred thirty-four thousand, three hundred seven".
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