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211141334343 = 32919312574673
BaseRepresentation
bin1100010010100100000…
…0010001010101000111
3202011222210200010000010
43010221000101111013
511424404140144333
6240555203321303
721153164505222
oct3045100212507
9664883603003
10211141334343
11815a9862635
1234b06980233
1316bab6002c4
14a30da625b9
15575b630563
hex3129011547

211141334343 has 16 divisors (see below), whose sum is σ = 292738410720. Its totient is φ = 135202873344.

The previous prime is 211141334317. The next prime is 211141334357. The reversal of 211141334343 is 343433141112.

It is a de Polignac number, because none of the positive numbers 2k-211141334343 is a prime.

It is a super-2 number, since 2×2111413343432 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211141334343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211141334303) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6270546 + ... + 6304127.

It is an arithmetic number, because the mean of its divisors is an integer number (18296150670).

Almost surely, 2211141334343 is an apocalyptic number.

211141334343 is a deficient number, since it is larger than the sum of its proper divisors (81597076377).

211141334343 is a wasteful number, since it uses less digits than its factorization.

211141334343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12574898.

The product of its digits is 10368, while the sum is 30.

Adding to 211141334343 its reverse (343433141112), we get a palindrome (554574475455).

The spelling of 211141334343 in words is "two hundred eleven billion, one hundred forty-one million, three hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 3 29 87 193 579 5597 16791 12574673 37724019 364665517 1093996551 2426911889 7280735667 70380444781 211141334343