Base | Representation |
---|---|
bin | 10011101010100000… |
… | …000001111101000101 |
3 | 2000111110222011020121 |
4 | 103222200001331011 |
5 | 321220204244331 |
6 | 13411045101541 |
7 | 1345141115656 |
oct | 235240017505 |
9 | 60443864217 |
10 | 21114134341 |
11 | 8a55418703 |
12 | 41130b78b1 |
13 | 1cb6466c21 |
14 | 104426352d |
15 | 838994c11 |
hex | 4ea801f45 |
21114134341 has 4 divisors (see below), whose sum is σ = 21403369132. Its totient is φ = 20824899552.
The previous prime is 21114134339. The next prime is 21114134417. The reversal of 21114134341 is 14343141112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11124131841 + 9990002500 = 105471^2 + 99950^2 .
It is a cyclic number.
It is not a de Polignac number, because 21114134341 - 21 = 21114134339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21114114341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144617286 + ... + 144617431.
It is an arithmetic number, because the mean of its divisors is an integer number (5350842283).
Almost surely, 221114134341 is an apocalyptic number.
It is an amenable number.
21114134341 is a deficient number, since it is larger than the sum of its proper divisors (289234791).
21114134341 is an equidigital number, since it uses as much as digits as its factorization.
21114134341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 289234790.
The product of its digits is 1152, while the sum is 25.
Adding to 21114134341 its reverse (14343141112), we get a palindrome (35457275453).
The spelling of 21114134341 in words is "twenty-one billion, one hundred fourteen million, one hundred thirty-four thousand, three hundred forty-one".
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