2111420131 has 2 divisors, whose sum is σ = 2111420132. Its totient is φ = 2111420130.

The previous prime is 2111420119. The next prime is 2111420159. The reversal of 2111420131 is 1310241112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2111420131 - 2¹⁵ = 2111387363 is a prime.

It is a super-2 number, since 2×2111420131² = 8916189939184114322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2111420161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055710065 + 1055710066.

It is an arithmetic number, because the mean of its divisors is an integer number (1055710066).

Almost surely, 2^2111420131 is an apocalyptic number.

2111420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111420131 is an equidigital number, since it uses as much as digits as its factorization.

2111420131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 2111420131 is about 45950.1918494363. The cubic root of 2111420131 is about 1282.8963001819.

Adding to 2111420131 its reverse (1310241112), we get a palindrome (3421661243).

The spelling of 2111420131 in words is "two billion, one hundred eleven million, four hundred twenty thousand, one hundred thirty-one".