Base | Representation |
---|---|
bin | 1100010010100100010… |
… | …0011010101100111011 |
3 | 202011222212201100001001 |
4 | 3010221010122230323 |
5 | 11424404424440212 |
6 | 240555242505431 |
7 | 21153206653216 |
oct | 3045104325473 |
9 | 664885640031 |
10 | 211142421307 |
11 | 815aa435254 |
12 | 34b07205277 |
13 | 16bab8c0c8c |
14 | a30dc6677d |
15 | 575b797657 |
hex | 312911ab3b |
211142421307 has 2 divisors, whose sum is σ = 211142421308. Its totient is φ = 211142421306.
The previous prime is 211142421289. The next prime is 211142421311. The reversal of 211142421307 is 703124241112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211142421307 - 211 = 211142419259 is a prime.
It is a super-2 number, since 2×2111424213072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211142421397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105571210653 + 105571210654.
It is an arithmetic number, because the mean of its divisors is an integer number (105571210654).
Almost surely, 2211142421307 is an apocalyptic number.
211142421307 is a deficient number, since it is larger than the sum of its proper divisors (1).
211142421307 is an equidigital number, since it uses as much as digits as its factorization.
211142421307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 211142421307 its reverse (703124241112), we get a palindrome (914266662419).
The spelling of 211142421307 in words is "two hundred eleven billion, one hundred forty-two million, four hundred twenty-one thousand, three hundred seven".
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