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21114300012 = 2231319233197103
BaseRepresentation
bin10011101010100000…
…101010011001101100
32000111111021120111120
4103222200222121230
5321220230100022
613411052420540
71345142405661
oct235240523154
960444246446
1021114300012
118a55521123
124113177750
131cb64c4460
1410442a7a68
158389c8d5c
hex4ea82a66c

21114300012 has 384 divisors, whose sum is σ = 61367255040. Its totient is φ = 5583790080.

The previous prime is 21114299977. The next prime is 21114300041. The reversal of 21114300012 is 21000341112.

It is a junction number, because it is equal to n+sod(n) for n = 21114299964 and 21114300000.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 204993153 + ... + 204993255.

It is an arithmetic number, because the mean of its divisors is an integer number (159810560).

Almost surely, 221114300012 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21114300012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30683627520).

21114300012 is an abundant number, since it is smaller than the sum of its proper divisors (40252955028).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21114300012 is a wasteful number, since it uses less digits than its factorization.

21114300012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 293 (or 291 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 21114300012 its reverse (21000341112), we get a palindrome (42114641124).

The spelling of 21114300012 in words is "twenty-one billion, one hundred fourteen million, three hundred thousand, twelve".