Base | Representation |
---|---|
bin | 10011101010100000… |
… | …101010101110010011 |
3 | 2000111111021122022102 |
4 | 103222200222232103 |
5 | 321220230120311 |
6 | 13411052431015 |
7 | 1345142412554 |
oct | 235240525623 |
9 | 60444248272 |
10 | 21114301331 |
11 | 8a55522112 |
12 | 411317846b |
13 | 1cb64c4c36 |
14 | 10442a832b |
15 | 8389c943b |
hex | 4ea82ab93 |
21114301331 has 2 divisors, whose sum is σ = 21114301332. Its totient is φ = 21114301330.
The previous prime is 21114301303. The next prime is 21114301391. The reversal of 21114301331 is 13310341112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21114301331 - 210 = 21114300307 is a prime.
It is a super-2 number, since 2×211143013312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21114301301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557150665 + 10557150666.
It is an arithmetic number, because the mean of its divisors is an integer number (10557150666).
Almost surely, 221114301331 is an apocalyptic number.
21114301331 is a deficient number, since it is larger than the sum of its proper divisors (1).
21114301331 is an equidigital number, since it uses as much as digits as its factorization.
21114301331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 21114301331 its reverse (13310341112), we get a palindrome (34424642443).
The spelling of 21114301331 in words is "twenty-one billion, one hundred fourteen million, three hundred one thousand, three hundred thirty-one".
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