Base | Representation |
---|---|
bin | 11110101110011111011… |
… | …110011100010101110001 |
3 | 21110212011101020100110101 |
4 | 132232133132130111301 |
5 | 234043330123000311 |
6 | 4254002313232401 |
7 | 305360023055104 |
oct | 36563736342561 |
9 | 7425141210411 |
10 | 2111504500081 |
11 | 744536275099 |
12 | 2a1282702701 |
13 | 12416366a8c2 |
14 | 742a97c873b |
15 | 39dd220cec1 |
hex | 1eb9f79c571 |
2111504500081 has 2 divisors, whose sum is σ = 2111504500082. Its totient is φ = 2111504500080.
The previous prime is 2111504500073. The next prime is 2111504500103. The reversal of 2111504500081 is 1800054051112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1490889840400 + 620614659681 = 1221020^2 + 787791^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111504500081 - 23 = 2111504500073 is a prime.
It is a super-2 number, since 2×21115045000812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111504506081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055752250040 + 1055752250041.
It is an arithmetic number, because the mean of its divisors is an integer number (1055752250041).
Almost surely, 22111504500081 is an apocalyptic number.
It is an amenable number.
2111504500081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111504500081 is an equidigital number, since it uses as much as digits as its factorization.
2111504500081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1600, while the sum is 28.
Adding to 2111504500081 its reverse (1800054051112), we get a palindrome (3911558551193).
The spelling of 2111504500081 in words is "two trillion, one hundred eleven billion, five hundred four million, five hundred thousand, eighty-one".
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