211200000111 has 6 divisors (see below), whose sum is σ = 305066666840. Its totient is φ = 140800000068.

The previous prime is 211200000097. The next prime is 211200000113. The reversal of 211200000111 is 111000002112.

It is a happy number.

It is not a de Polignac number, because 211200000111 - 2¹⁸ = 211199737967 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9), and also a Moran number because the ratio is a prime number: 23466666679 = 211200000111 / (2 + 1 + 1 + 2 + 0 + 0 + 0 + 0 + 0 + 1 + 1 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211200000093 and 211200000102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211200000113) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11733333331 + ... + 11733333348.

Almost surely, 2^211200000111 is an apocalyptic number.

211200000111 is a deficient number, since it is larger than the sum of its proper divisors (93866666729).

211200000111 is a wasteful number, since it uses less digits than its factorization.

211200000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23466666685 (or 23466666682 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 9.

Adding to 211200000111 its reverse (111000002112), we get a palindrome (322200002223).

The spelling of 211200000111 in words is "two hundred eleven billion, two hundred million, one hundred eleven", and thus it is an aban number.