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2112000041 is a prime number
BaseRepresentation
bin111110111100010…
…1001000000101001
312110012002201101202
41331320221000221
513311133000131
6545323253545
7103223463344
oct17570510051
95405081352
102112000041
11994194988
124ab37a2b5
1327872cb88
141606d145b
15c5637bcb
hex7de29029

2112000041 has 2 divisors, whose sum is σ = 2112000042. Its totient is φ = 2112000040.

The previous prime is 2112000031. The next prime is 2112000097. The reversal of 2112000041 is 1400002112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2012419600 + 99580441 = 44860^2 + 9979^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112000041 - 26 = 2111999977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2111999986 and 2112000031.

It is not a weakly prime, because it can be changed into another prime (2112000031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056000020 + 1056000021.

It is an arithmetic number, because the mean of its divisors is an integer number (1056000021).

Almost surely, 22112000041 is an apocalyptic number.

It is an amenable number.

2112000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112000041 is an equidigital number, since it uses as much as digits as its factorization.

2112000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 11.

The square root of 2112000041 is about 45956.5016183782. The cubic root of 2112000041 is about 1283.0137403007.

Adding to 2112000041 its reverse (1400002112), we get a palindrome (3512002153).

The spelling of 2112000041 in words is "two billion, one hundred twelve million, forty-one", and thus it is an aban number.