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2112000113 is a prime number
BaseRepresentation
bin111110111100010…
…1001000001110001
312110012002201111102
41331320221001301
513311133000423
6545323254145
7103223463506
oct17570510161
95405081442
102112000113
11994194a43
124ab37a355
1327872cc12
141606d14ad
15c5637c28
hex7de29071

2112000113 has 2 divisors, whose sum is σ = 2112000114. Its totient is φ = 2112000112.

The previous prime is 2112000097. The next prime is 2112000179. The reversal of 2112000113 is 3110002112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1381757584 + 730242529 = 37172^2 + 27023^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112000113 - 24 = 2112000097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2112000094 and 2112000103.

It is not a weakly prime, because it can be changed into another prime (2112000713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056000056 + 1056000057.

It is an arithmetic number, because the mean of its divisors is an integer number (1056000057).

Almost surely, 22112000113 is an apocalyptic number.

It is an amenable number.

2112000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112000113 is an equidigital number, since it uses as much as digits as its factorization.

2112000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2112000113 is about 45956.5024017277. The cubic root of 2112000113 is about 1283.0137548804.

Adding to 2112000113 its reverse (3110002112), we get a palindrome (5222002225).

The spelling of 2112000113 in words is "two billion, one hundred twelve million, one hundred thirteen", and thus it is an aban number.