Base | Representation |
---|---|
bin | 110000000001010111011010… |
… | …111100011001011001011011 |
3 | 1000200210112101002221122011201 |
4 | 300001113122330121121123 |
5 | 210140300301112040323 |
6 | 2025103553032535031 |
7 | 62325463236424564 |
oct | 6001273274313133 |
9 | 1020715332848151 |
10 | 211200100111963 |
11 | 613275065a1016 |
12 | 1b82bbb2251477 |
13 | 90b0112684841 |
14 | 3a221d469b16b |
15 | 1963bec8958ad |
hex | c015daf1965b |
211200100111963 has 2 divisors, whose sum is σ = 211200100111964. Its totient is φ = 211200100111962.
The previous prime is 211200100111937. The next prime is 211200100112081. The reversal of 211200100111963 is 369111001002112.
211200100111963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211200100111963 is a prime.
It is not a weakly prime, because it can be changed into another prime (211200100181963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600050055981 + 105600050055982.
It is an arithmetic number, because the mean of its divisors is an integer number (105600050055982).
Almost surely, 2211200100111963 is an apocalyptic number.
211200100111963 is a deficient number, since it is larger than the sum of its proper divisors (1).
211200100111963 is an equidigital number, since it uses as much as digits as its factorization.
211200100111963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 211200100111963 in words is "two hundred eleven trillion, two hundred billion, one hundred million, one hundred eleven thousand, nine hundred sixty-three".
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