Base | Representation |
---|---|
bin | 110000000001010111011011… |
… | …100010000111011110010001 |
3 | 1000200210112101210120000000221 |
4 | 300001113123202013132101 |
5 | 210140300311130000032 |
6 | 2025103554024513041 |
7 | 62325463416446665 |
oct | 6001273342073621 |
9 | 1020715353500027 |
10 | 211200110000017 |
11 | 61327511135066 |
12 | 1b82bbb561b781 |
13 | 90b0114737468 |
14 | 3a221d5b128a5 |
15 | 1963bed69a597 |
hex | c015db887791 |
211200110000017 has 2 divisors, whose sum is σ = 211200110000018. Its totient is φ = 211200110000016.
The previous prime is 211200109999981. The next prime is 211200110000029. The reversal of 211200110000017 is 710000011002112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 206341043659776 + 4859066340241 = 14364576^2 + 2204329^2 .
It is a cyclic number.
It is not a de Polignac number, because 211200110000017 - 223 = 211200101611409 is a prime.
It is not a weakly prime, because it can be changed into another prime (211200110000057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600055000008 + 105600055000009.
It is an arithmetic number, because the mean of its divisors is an integer number (105600055000009).
Almost surely, 2211200110000017 is an apocalyptic number.
It is an amenable number.
211200110000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
211200110000017 is an equidigital number, since it uses as much as digits as its factorization.
211200110000017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 211200110000017 its reverse (710000011002112), we get a palindrome (921200121002129).
The spelling of 211200110000017 in words is "two hundred eleven trillion, two hundred billion, one hundred ten million, seventeen", and thus it is an aban number.
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