2112010011113 has 2 divisors, whose sum is σ = 2112010011114. Its totient is φ = 2112010011112.

The previous prime is 2112010011101. The next prime is 2112010011143. The reversal of 2112010011113 is 3111100102112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1257869916304 + 854140094809 = 1121548^2 + 924197^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2112010011113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2112010011143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056005005556 + 1056005005557.

It is an arithmetic number, because the mean of its divisors is an integer number (1056005005557).

Almost surely, 2^{2112010011113} is an apocalyptic number.

It is an amenable number.

2112010011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112010011113 is an equidigital number, since it uses as much as digits as its factorization.

2112010011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 2112010011113 its reverse (3111100102112), we get a palindrome (5223110113225).

Subtracting 2112010011113 from its reverse (3111100102112), we obtain a palindrome (999090090999).

The spelling of 2112010011113 in words is "two trillion, one hundred twelve billion, ten million, eleven thousand, one hundred thirteen".