Base | Representation |
---|---|
bin | 11110101110111101101… |
… | …110110010100101111101 |
3 | 21110220110202101012101221 |
4 | 132232331232302211331 |
5 | 234100400044231023 |
6 | 4254124525033341 |
7 | 305405425443112 |
oct | 36567556624575 |
9 | 7426422335357 |
10 | 2112012102013 |
11 | 744776853a20 |
12 | 2a13a46b5851 |
13 | 124214884b88 |
14 | 74316d9c909 |
15 | 39e11a7885d |
hex | 1ebbdbb297d |
2112012102013 has 32 divisors (see below), whose sum is σ = 2473048537344. Its totient is φ = 1784302080000.
The previous prime is 2112012101923. The next prime is 2112012102023. The reversal of 2112012102013 is 3102012102112.
It is a de Polignac number, because none of the positive numbers 2k-2112012102013 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112012102023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2077473 + ... + 2922313.
It is an arithmetic number, because the mean of its divisors is an integer number (77282766792).
Almost surely, 22112012102013 is an apocalyptic number.
2112012102013 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2112012102013 is a deficient number, since it is larger than the sum of its proper divisors (361036435331).
2112012102013 is a wasteful number, since it uses less digits than its factorization.
2112012102013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 845157.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2112012102013 its reverse (3102012102112), we get a palindrome (5214024204125).
Subtracting 2112012102013 from its reverse (3102012102112), we obtain a palindrome (990000000099).
The spelling of 2112012102013 in words is "two trillion, one hundred twelve billion, twelve million, one hundred two thousand, thirteen".
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