2112020212013 has 4 divisors (see below), whose sum is σ = 2223179170560. Its totient is φ = 2000861253468.

The previous prime is 2112020212007. The next prime is 2112020212087. The reversal of 2112020212013 is 3102120202112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2112020212013 - 2⁸ = 2112020211757 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112020211982 and 2112020212000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112020211013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55579479245 + ... + 55579479282.

It is an arithmetic number, because the mean of its divisors is an integer number (555794792640).

Almost surely, 2^{2112020212013} is an apocalyptic number.

It is an amenable number.

2112020212013 is a deficient number, since it is larger than the sum of its proper divisors (111158958547).

2112020212013 is a wasteful number, since it uses less digits than its factorization.

2112020212013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111158958546.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 2112020212013 its reverse (3102120202112), we get a palindrome (5214140414125).

Subtracting 2112020212013 from its reverse (3102120202112), we obtain a palindrome (990099990099).

The spelling of 2112020212013 in words is "two trillion, one hundred twelve billion, twenty million, two hundred twelve thousand, thirteen".