Base | Representation |
---|---|
bin | 110000000001011001011000… |
… | …110100111111111110000110 |
3 | 1000200210201211022000211212202 |
4 | 300001121120310333332012 |
5 | 210140314112244231042 |
6 | 2025104542400114502 |
7 | 62325566463150161 |
oct | 6001313064777606 |
9 | 1020721738024782 |
10 | 211202212102022 |
11 | 6132839a779449 |
12 | 1b8304a1605a32 |
13 | 90b038b0accbb |
14 | 3a22354d88ad8 |
15 | 1963cc2eca632 |
hex | c01658d3ff86 |
211202212102022 has 4 divisors (see below), whose sum is σ = 316803318153036. Its totient is φ = 105601106051010.
The previous prime is 211202212101997. The next prime is 211202212102031. The reversal of 211202212102022 is 220201212202112.
211202212102022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 211202212101985 and 211202212102003.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52800553025504 + ... + 52800553025507.
It is an arithmetic number, because the mean of its divisors is an integer number (79200829538259).
Almost surely, 2211202212102022 is an apocalyptic number.
211202212102022 is a deficient number, since it is larger than the sum of its proper divisors (105601106051014).
211202212102022 is a wasteful number, since it uses less digits than its factorization.
211202212102022 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105601106051013.
The product of its (nonzero) digits is 256, while the sum is 20.
Adding to 211202212102022 its reverse (220201212202112), we get a palindrome (431403424304134).
The spelling of 211202212102022 in words is "two hundred eleven trillion, two hundred two billion, two hundred twelve million, one hundred two thousand, twenty-two".
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