Base | Representation |
---|---|
bin | 10011101010110111… |
… | …101010100110010011 |
3 | 2000111220121221021022 |
4 | 103222313222212103 |
5 | 321223301031011 |
6 | 13411425550055 |
7 | 1345244562335 |
oct | 235267524623 |
9 | 60456557238 |
10 | 21120330131 |
11 | 8a5896a69a |
12 | 41151a532b |
13 | 1cb7826084 |
14 | 1044dd7455 |
15 | 8392ba8db |
hex | 4eadea993 |
21120330131 has 2 divisors, whose sum is σ = 21120330132. Its totient is φ = 21120330130.
The previous prime is 21120330113. The next prime is 21120330151. The reversal of 21120330131 is 13103302112.
Together with previous prime (21120330113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21120330131 - 218 = 21120067987 is a prime.
It is a super-3 number, since 3×211203301313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (21120330151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560165065 + 10560165066.
It is an arithmetic number, because the mean of its divisors is an integer number (10560165066).
Almost surely, 221120330131 is an apocalyptic number.
21120330131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120330131 is an equidigital number, since it uses as much as digits as its factorization.
21120330131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 21120330131 its reverse (13103302112), we get a palindrome (34223632243).
The spelling of 21120330131 in words is "twenty-one billion, one hundred twenty million, three hundred thirty thousand, one hundred thirty-one".
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