Base | Representation |
---|---|
bin | 11110101111000000010… |
… | …010110111100100110001 |
3 | 21110220120202022102210201 |
4 | 132233000102313210301 |
5 | 234100442102122113 |
6 | 4254133102555201 |
7 | 305406460154434 |
oct | 36570022674461 |
9 | 7426522272721 |
10 | 2112055114033 |
11 | 744799061547 |
12 | 2a13b6b98b01 |
13 | 124220764687 |
14 | 7431c99781b |
15 | 39e15722cdd |
hex | 1ebc04b7931 |
2112055114033 has 2 divisors, whose sum is σ = 2112055114034. Its totient is φ = 2112055114032.
The previous prime is 2112055114009. The next prime is 2112055114049. The reversal of 2112055114033 is 3304115502112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1135539590689 + 976515523344 = 1065617^2 + 988188^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112055114033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112055113992 and 2112055114010.
It is not a weakly prime, because it can be changed into another prime (2112053114033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056027557016 + 1056027557017.
It is an arithmetic number, because the mean of its divisors is an integer number (1056027557017).
Almost surely, 22112055114033 is an apocalyptic number.
It is an amenable number.
2112055114033 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112055114033 is an equidigital number, since it uses as much as digits as its factorization.
2112055114033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 28.
The spelling of 2112055114033 in words is "two trillion, one hundred twelve billion, fifty-five million, one hundred fourteen thousand, thirty-three".
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