Base | Representation |
---|---|
bin | 11110101111000001111… |
… | …111100101111101001001 |
3 | 21110220122201221110112212 |
4 | 132233001333211331021 |
5 | 234101021401144221 |
6 | 4254140001514505 |
7 | 305410254342323 |
oct | 36570177457511 |
9 | 7426581843485 |
10 | 2112083615561 |
11 | 744803159127 |
12 | 2a1404642a35 |
13 | 12422663359a |
14 | 74322696613 |
15 | 39e17ea2b5b |
hex | 1ebc1fe5f49 |
2112083615561 has 2 divisors, whose sum is σ = 2112083615562. Its totient is φ = 2112083615560.
The previous prime is 2112083615533. The next prime is 2112083615569. The reversal of 2112083615561 is 1655163802112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1250192334400 + 861891281161 = 1118120^2 + 928381^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112083615561 - 26 = 2112083615497 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112083615569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056041807780 + 1056041807781.
It is an arithmetic number, because the mean of its divisors is an integer number (1056041807781).
Almost surely, 22112083615561 is an apocalyptic number.
It is an amenable number.
2112083615561 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112083615561 is an equidigital number, since it uses as much as digits as its factorization.
2112083615561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 41.
The spelling of 2112083615561 in words is "two trillion, one hundred twelve billion, eighty-three million, six hundred fifteen thousand, five hundred sixty-one".
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