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211210203319987 is a prime number
BaseRepresentation
bin110000000001100000110101…
…001001000100111010110011
31000200211111110012220210002111
4300001200311021010322303
5210140431444022214422
62025112343343430151
762326301506322554
oct6001406511047263
91020744405823074
10211210203319987
1161330820598813
121b831b518b5357
1390b1062869a41
143a228b240832b
1519640de83da77
hexc01835244eb3

211210203319987 has 2 divisors, whose sum is σ = 211210203319988. Its totient is φ = 211210203319986.

The previous prime is 211210203319949. The next prime is 211210203320041. The reversal of 211210203319987 is 789913302012112.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211210203319987 is a prime.

It is a super-2 number, since 2×2112102033199872 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211210203319987.

It is not a weakly prime, because it can be changed into another prime (211210203319387) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605101659993 + 105605101659994.

It is an arithmetic number, because the mean of its divisors is an integer number (105605101659994).

Almost surely, 2211210203319987 is an apocalyptic number.

211210203319987 is a deficient number, since it is larger than the sum of its proper divisors (1).

211210203319987 is an equidigital number, since it uses as much as digits as its factorization.

211210203319987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 49.

The spelling of 211210203319987 in words is "two hundred eleven trillion, two hundred ten billion, two hundred three million, three hundred nineteen thousand, nine hundred eighty-seven".