Base | Representation |
---|---|
bin | 1100010010110100011… |
… | …1011100010010111010 |
3 | 202012011121111002211101 |
4 | 3010231013130102322 |
5 | 11430024320320010 |
6 | 241010110122014 |
7 | 21154663060552 |
oct | 3045507342272 |
9 | 665147432741 |
10 | 211210323130 |
11 | 816347a2964 |
12 | 34b25ab030a |
13 | 16bbc9a6781 |
14 | a318ca0162 |
15 | 576270b73a |
hex | 312d1dc4ba |
211210323130 has 16 divisors (see below), whose sum is σ = 392442407424. Its totient is φ = 81758834640.
The previous prime is 211210323089. The next prime is 211210323131. The reversal of 211210323130 is 31323012112.
211210323130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 211210323098 and 211210323107.
It is not an unprimeable number, because it can be changed into a prime (211210323131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 340661502 + ... + 340662121.
It is an arithmetic number, because the mean of its divisors is an integer number (24527650464).
Almost surely, 2211210323130 is an apocalyptic number.
211210323130 is a deficient number, since it is larger than the sum of its proper divisors (181232084294).
211210323130 is a wasteful number, since it uses less digits than its factorization.
211210323130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 681323661.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 211210323130 its reverse (31323012112), we get a palindrome (242533335242).
The spelling of 211210323130 in words is "two hundred eleven billion, two hundred ten million, three hundred twenty-three thousand, one hundred thirty".
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