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211211021122 = 2105605510561
BaseRepresentation
bin1100010010110100101…
…0000110101101000010
3202012011122210120021221
43010231022012231002
511430030010133442
6241010133105254
721155002025533
oct3045512065502
9665148716257
10211211021122
118163512a312
1234b2618822a
1316bbcb8c39a
14a31900268a
1557627e8467
hex312d286b42

211211021122 has 4 divisors (see below), whose sum is σ = 316816531686. Its totient is φ = 105605510560.

The previous prime is 211211021069. The next prime is 211211021143. The reversal of 211211021122 is 221120112112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 151631581201 + 59579439921 = 389399^2 + 244089^2 .

It is a super-2 number, since 2×2112110211222 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211211021096 and 211211021105.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52802755279 + ... + 52802755282.

Almost surely, 2211211021122 is an apocalyptic number.

211211021122 is a deficient number, since it is larger than the sum of its proper divisors (105605510564).

211211021122 is a wasteful number, since it uses less digits than its factorization.

211211021122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105605510563.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 211211021122 its reverse (221120112112), we get a palindrome (432331133234).

The spelling of 211211021122 in words is "two hundred eleven billion, two hundred eleven million, twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 105605510561 211211021122