Base | Representation |
---|---|
bin | 110000000001100001101010… |
… | …101101101110111111011011 |
3 | 1000200211120202212011122120222 |
4 | 300001201222231232333123 |
5 | 210140440314120400242 |
6 | 2025113012452110255 |
7 | 62326333002111464 |
oct | 6001415255567733 |
9 | 1020746685148528 |
10 | 211211102121947 |
11 | 61331141981a54 |
12 | 1b83216290538b |
13 | 90b1176b34015 |
14 | 3a22959931d6b |
15 | 19641436d05d2 |
hex | c0186ab6efdb |
211211102121947 has 2 divisors, whose sum is σ = 211211102121948. Its totient is φ = 211211102121946.
The previous prime is 211211102121941. The next prime is 211211102122051. The reversal of 211211102121947 is 749121201112112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211211102121947 - 218 = 211211101859803 is a prime.
It is a super-2 number, since 2×2112111021219472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211211102121941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605551060973 + 105605551060974.
It is an arithmetic number, because the mean of its divisors is an integer number (105605551060974).
Almost surely, 2211211102121947 is an apocalyptic number.
211211102121947 is a deficient number, since it is larger than the sum of its proper divisors (1).
211211102121947 is an equidigital number, since it uses as much as digits as its factorization.
211211102121947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 35.
The spelling of 211211102121947 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred two million, one hundred twenty-one thousand, nine hundred forty-seven".
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