Base | Representation |
---|---|
bin | 1001100110101101001000… |
… | …10001010111111001111110 |
3 | 2202210011021111010011111102 |
4 | 10303112210101113321332 |
5 | 10232022013203242342 |
6 | 112530523140453102 |
7 | 4306643541421436 |
oct | 463264421277176 |
9 | 82704244104442 |
10 | 21121110212222 |
11 | 680345a0a7a09 |
12 | 24514b50aa192 |
13 | ba2934781937 |
14 | 5303a52472c6 |
15 | 26961dca4832 |
hex | 1335a4457e7e |
21121110212222 has 4 divisors (see below), whose sum is σ = 31681665318336. Its totient is φ = 10560555106110.
The previous prime is 21121110212197. The next prime is 21121110212281. The reversal of 21121110212222 is 22221201112112.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×211211102122223 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 21121110212194 and 21121110212203.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5280277553054 + ... + 5280277553057.
It is an arithmetic number, because the mean of its divisors is an integer number (7920416329584).
Almost surely, 221121110212222 is an apocalyptic number.
21121110212222 is a deficient number, since it is larger than the sum of its proper divisors (10560555106114).
21121110212222 is a wasteful number, since it uses less digits than its factorization.
21121110212222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10560555106113.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 21121110212222 its reverse (22221201112112), we get a palindrome (43342311324334).
The spelling of 21121110212222 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred ten million, two hundred twelve thousand, two hundred twenty-two".
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