Base | Representation |
---|---|
bin | 11110101111000011101… |
… | …000111001100110001011 |
3 | 21110220201122212222021101 |
4 | 132233003220321212023 |
5 | 234101100433034011 |
6 | 4254142425322231 |
7 | 305411041106122 |
oct | 36570350714613 |
9 | 7426648788241 |
10 | 2112111221131 |
11 | 7448177a364a |
12 | 2a1411936377 |
13 | 12422c27a742 |
14 | 74326200ab9 |
15 | 39e1a6072c1 |
hex | 1ebc3a3998b |
2112111221131 has 2 divisors, whose sum is σ = 2112111221132. Its totient is φ = 2112111221130.
The previous prime is 2112111221119. The next prime is 2112111221141. The reversal of 2112111221131 is 1311221112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112111221131 - 211 = 2112111219083 is a prime.
It is a super-2 number, since 2×21121112211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112111221099 and 2112111221108.
It is not a weakly prime, because it can be changed into another prime (2112111221141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056055610565 + 1056055610566.
It is an arithmetic number, because the mean of its divisors is an integer number (1056055610566).
Almost surely, 22112111221131 is an apocalyptic number.
2112111221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112111221131 is an equidigital number, since it uses as much as digits as its factorization.
2112111221131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 19.
Adding to 2112111221131 its reverse (1311221112112), we get a palindrome (3423332333243).
The spelling of 2112111221131 in words is "two trillion, one hundred twelve billion, one hundred eleven million, two hundred twenty-one thousand, one hundred thirty-one".
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