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21121113014 = 210560556507
BaseRepresentation
bin10011101010111010…
…101001101110110110
32000111222002201011222
4103222322221232312
5321224001104024
613411454430342
71345254332651
oct235272515666
960458081158
1021121113014
118a59354901
1241155023b2
131cb7a3b511
14104515c898
158393c285e
hex4eaea9bb6

21121113014 has 4 divisors (see below), whose sum is σ = 31681669524. Its totient is φ = 10560556506.

The previous prime is 21121113007. The next prime is 21121113017. The reversal of 21121113014 is 41031112112.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×211211130142 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21121112983 and 21121113001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21121113017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5280278252 + ... + 5280278255.

It is an arithmetic number, because the mean of its divisors is an integer number (7920417381).

Almost surely, 221121113014 is an apocalyptic number.

21121113014 is a deficient number, since it is larger than the sum of its proper divisors (10560556510).

21121113014 is a wasteful number, since it uses less digits than its factorization.

21121113014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10560556509.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 21121113014 its reverse (41031112112), we get a palindrome (62152225126).

The spelling of 21121113014 in words is "twenty-one billion, one hundred twenty-one million, one hundred thirteen thousand, fourteen".

Divisors: 1 2 10560556507 21121113014