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211211133233 is a prime number
BaseRepresentation
bin1100010010110100101…
…0100010000100110001
3202012011200000021002012
43010231022202010301
511430030022230413
6241010135332305
721155003003432
oct3045512420461
9665150007065
10211211133233
11816351a6571
1234b26221095
1316bbcbcb419
14a319031489
15576281b7a8
hex312d2a2131

211211133233 has 2 divisors, whose sum is σ = 211211133234. Its totient is φ = 211211133232.

The previous prime is 211211133143. The next prime is 211211133241. The reversal of 211211133233 is 332331112112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 210453397504 + 757735729 = 458752^2 + 27527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211211133233 is a prime.

It is a super-2 number, since 2×2112111332332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211211133199 and 211211133208.

It is not a weakly prime, because it can be changed into another prime (211211133293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605566616 + 105605566617.

It is an arithmetic number, because the mean of its divisors is an integer number (105605566617).

Almost surely, 2211211133233 is an apocalyptic number.

It is an amenable number.

211211133233 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211133233 is an equidigital number, since it uses as much as digits as its factorization.

211211133233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 23.

Adding to 211211133233 its reverse (332331112112), we get a palindrome (543542245345).

The spelling of 211211133233 in words is "two hundred eleven billion, two hundred eleven million, one hundred thirty-three thousand, two hundred thirty-three".