211211203240445 has 4 divisors (see below), whose sum is σ = 253453443888540. Its totient is φ = 168968962592352.

The previous prime is 211211203240421. The next prime is 211211203240451. The reversal of 211211203240445 is 544042302112112.

211211203240445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 127900786718329 + 83310416522116 = 11309323^2 + 9127454^2 .

It is a cyclic number.

It is not a de Polignac number, because 211211203240445 - 2¹⁸ = 211211202978301 is a prime.

It is a super-2 number, since 2×211211203240445² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21121120324040 + ... + 21121120324049.

It is an arithmetic number, because the mean of its divisors is an integer number (63363360972135).

Almost surely, 2^{211211203240445} is an apocalyptic number.

It is an amenable number.

211211203240445 is a deficient number, since it is larger than the sum of its proper divisors (42242240648095).

211211203240445 is an equidigital number, since it uses as much as digits as its factorization.

211211203240445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42242240648094.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 211211203240445 its reverse (544042302112112), we get a palindrome (755253505352557).

The spelling of 211211203240445 in words is "two hundred eleven trillion, two hundred eleven billion, two hundred three million, two hundred forty thousand, four hundred forty-five".