Base | Representation |
---|---|
bin | 111110111100100… |
… | …0100010111100111 |
3 | 12110012022102010012 |
4 | 1331321010113213 |
5 | 13311200041403 |
6 | 545325520435 |
7 | 103224441143 |
oct | 17571042747 |
9 | 5405272105 |
10 | 2112112103 |
11 | 9942610a2 |
12 | 4ab41311b |
13 | 27876bb9a |
14 | 160720223 |
15 | c565aed8 |
hex | 7de445e7 |
2112112103 has 8 divisors (see below), whose sum is σ = 2205500928. Its totient is φ = 2018853144.
The previous prime is 2112112097. The next prime is 2112112117. The reversal of 2112112103 is 3012112112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2112112103 - 212 = 2112108007 is a prime.
It is a super-2 number, since 2×21121121032 = 8922035071278165218, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112112603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1550 + ... + 65012.
It is an arithmetic number, because the mean of its divisors is an integer number (275687616).
Almost surely, 22112112103 is an apocalyptic number.
2112112103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2112112103 is a deficient number, since it is larger than the sum of its proper divisors (93388825).
2112112103 is a wasteful number, since it uses less digits than its factorization.
2112112103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64933.
The product of its (nonzero) digits is 24, while the sum is 14.
The square root of 2112112103 is about 45957.7208203366. The cubic root of 2112112103 is about 1283.0364319894.
Adding to 2112112103 its reverse (3012112112), we get a palindrome (5124224215).
Subtracting 2112112103 from its reverse (3012112112), we obtain a palindrome (900000009).
The spelling of 2112112103 in words is "two billion, one hundred twelve million, one hundred twelve thousand, one hundred three".
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