Base | Representation |
---|---|
bin | 11110101111000011101… |
… | …100010111011111010011 |
3 | 21110220201201121011000022 |
4 | 132233003230113133103 |
5 | 234101101201130003 |
6 | 4254142501014055 |
7 | 305411051612651 |
oct | 36570354273723 |
9 | 7426651534008 |
10 | 2112112130003 |
11 | 744818264487 |
12 | 2a14120b432b |
13 | 12422c508335 |
14 | 74326399dd1 |
15 | 39e1a736738 |
hex | 1ebc3b177d3 |
2112112130003 has 2 divisors, whose sum is σ = 2112112130004. Its totient is φ = 2112112130002.
The previous prime is 2112112129997. The next prime is 2112112130039. The reversal of 2112112130003 is 3000312112112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112112130003 - 214 = 2112112113619 is a prime.
It is a super-2 number, since 2×21121121300032 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (2112112130803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056056065001 + 1056056065002.
It is an arithmetic number, because the mean of its divisors is an integer number (1056056065002).
Almost surely, 22112112130003 is an apocalyptic number.
2112112130003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112112130003 is an equidigital number, since it uses as much as digits as its factorization.
2112112130003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2112112130003 its reverse (3000312112112), we get a palindrome (5112424242115).
The spelling of 2112112130003 in words is "two trillion, one hundred twelve billion, one hundred twelve million, one hundred thirty thousand, three".
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