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211211220023 = 673152406269
BaseRepresentation
bin1100010010110100101…
…0110111010000110111
3202012011200011200010122
43010231022313100313
511430030033020043
6241010141242155
721155003514446
oct3045512672067
9665150150118
10211211220023
11816352557a1
1234b2626335b
1316bbcc2ba8b
14a319054d5d
155762837368
hex312d2b7437

211211220023 has 4 divisors (see below), whose sum is σ = 214363626360. Its totient is φ = 208058813688.

The previous prime is 211211220001. The next prime is 211211220079. The reversal of 211211220023 is 320022112112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 211211220023 - 212 = 211211215927 is a prime.

It is a super-2 number, since 2×2112112200232 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211211219983 and 211211220010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211211220223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1576203068 + ... + 1576203201.

It is an arithmetic number, because the mean of its divisors is an integer number (53590906590).

Almost surely, 2211211220023 is an apocalyptic number.

211211220023 is a deficient number, since it is larger than the sum of its proper divisors (3152406337).

211211220023 is an equidigital number, since it uses as much as digits as its factorization.

211211220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3152406336.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 211211220023 its reverse (320022112112), we get a palindrome (531233332135).

The spelling of 211211220023 in words is "two hundred eleven billion, two hundred eleven million, two hundred twenty thousand, twenty-three".

Divisors: 1 67 3152406269 211211220023