Base | Representation |
---|---|
bin | 1001100110101101001011… |
… | …00000101011000011000000 |
3 | 2202210011022221020021222010 |
4 | 10303112211200223003000 |
5 | 10232022034014000000 |
6 | 112530525202212520 |
7 | 4306644213211263 |
oct | 463264540530300 |
9 | 82704287207863 |
10 | 21121131000000 |
11 | 680346a906099 |
12 | 2451500054140 |
13 | ba2938b7c7b5 |
14 | 5303a7cd8cda |
15 | 269620a0dd50 |
hex | 1335a582b0c0 |
21121131000000 has 392 divisors, whose sum is σ = 70056470453200. Its totient is φ = 5615884800000.
The previous prime is 21121130999959. The next prime is 21121131000019. The reversal of 21121131000000 is 13112112.
It is a super-2 number, since 2×211211310000002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a self number, because there is not a number n which added to its sum of digits gives 21121131000000.
It is an unprimeable number.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 1046989914 + ... + 1047010086.
It is an arithmetic number, because the mean of its divisors is an integer number (178715485850).
Almost surely, 221121131000000 is an apocalyptic number.
21121131000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 21121131000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (35028235226600).
21121131000000 is an abundant number, since it is smaller than the sum of its proper divisors (48935339453200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21121131000000 is an frugal number, since it uses more digits than its factorization.
21121131000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20567 (or 20532 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 21121131000000 its reverse (13112112), we get a palindrome (21121144112112).
It can be divided in two parts, 2112113 and 1000000, that added together give a palindrome (3112113).
The spelling of 21121131000000 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred thirty-one million", and thus it is an aban number.
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