Base | Representation |
---|---|
bin | 1001100110101101001011… |
… | …00101010000100000011101 |
3 | 2202210011100000111100211010 |
4 | 10303112211211100200131 |
5 | 10232022034320431023 |
6 | 112530525244045433 |
7 | 4306644226345554 |
oct | 463264545204035 |
9 | 82704300440733 |
10 | 21121132202013 |
11 | 6803470557198 |
12 | 2451500533879 |
13 | ba29391b094c |
14 | 5303a812cd9b |
15 | 269620b9a093 |
hex | 1335a595081d |
21121132202013 has 32 divisors (see below), whose sum is σ = 28316884746240. Its totient is φ = 14003273934720.
The previous prime is 21121132202003. The next prime is 21121132202039. The reversal of 21121132202013 is 31020223112112.
It is not a de Polignac number, because 21121132202013 - 29 = 21121132201501 is a prime.
It is a super-2 number, since 2×211211322020132 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21121132202003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1670044456 + ... + 1670057102.
It is an arithmetic number, because the mean of its divisors is an integer number (884902648320).
Almost surely, 221121132202013 is an apocalyptic number.
It is an amenable number.
21121132202013 is a deficient number, since it is larger than the sum of its proper divisors (7195752544227).
21121132202013 is a wasteful number, since it uses less digits than its factorization.
21121132202013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16497.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 21121132202013 its reverse (31020223112112), we get a palindrome (52141355314125).
The spelling of 21121132202013 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred thirty-two million, two hundred two thousand, thirteen".
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