Base | Representation |
---|---|
bin | 1001100110101101010011… |
… | …00111111001010001010011 |
3 | 2202210011111202001222002121 |
4 | 10303112221213321101103 |
5 | 10232022204200032011 |
6 | 112530540105155111 |
7 | 4306646011550545 |
oct | 463265147712123 |
9 | 82704452058077 |
10 | 21121200002131 |
11 | 68034a5855449 |
12 | 245151b18ba97 |
13 | ba294a25c068 |
14 | 5303b313b695 |
15 | 269626adde71 |
hex | 1335a99f9453 |
21121200002131 has 2 divisors, whose sum is σ = 21121200002132. Its totient is φ = 21121200002130.
The previous prime is 21121200002099. The next prime is 21121200002219. The reversal of 21121200002131 is 13120000212112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21121200002131 - 25 = 21121200002099 is a prime.
It is a super-2 number, since 2×211212000021312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21121200002831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560600001065 + 10560600001066.
It is an arithmetic number, because the mean of its divisors is an integer number (10560600001066).
Almost surely, 221121200002131 is an apocalyptic number.
21121200002131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121200002131 is an equidigital number, since it uses as much as digits as its factorization.
21121200002131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 21121200002131 its reverse (13120000212112), we get a palindrome (34241200214243).
The spelling of 21121200002131 in words is "twenty-one trillion, one hundred twenty-one billion, two hundred million, two thousand, one hundred thirty-one".
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