Base | Representation |
---|---|
bin | 11110101111000100001… |
… | …110100101111011000101 |
3 | 21110220202100110222022021 |
4 | 132233010032211323011 |
5 | 234101111000231041 |
6 | 4254143421203141 |
7 | 305411221101310 |
oct | 36570416457305 |
9 | 7426670428267 |
10 | 2112121102021 |
11 | 744822332277 |
12 | 2a14151004b1 |
13 | 12423132a018 |
14 | 74327653977 |
15 | 39e1b409cd1 |
hex | 1ebc43a5ec5 |
2112121102021 has 4 divisors (see below), whose sum is σ = 2413852688032. Its totient is φ = 1810389516012.
The previous prime is 2112121101977. The next prime is 2112121102027. The reversal of 2112121102021 is 1202011212112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 2112121102021 - 211 = 2112121099973 is a prime.
It is a super-2 number, since 2×21121211020212 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2112121101986 and 2112121102004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112121102027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150865792995 + ... + 150865793008.
It is an arithmetic number, because the mean of its divisors is an integer number (603463172008).
Almost surely, 22112121102021 is an apocalyptic number.
It is an amenable number.
2112121102021 is a deficient number, since it is larger than the sum of its proper divisors (301731586011).
2112121102021 is an equidigital number, since it uses as much as digits as its factorization.
2112121102021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 301731586010.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 2112121102021 its reverse (1202011212112), we get a palindrome (3314132314133).
The spelling of 2112121102021 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, one hundred two thousand, twenty-one".
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