Base | Representation |
---|---|
bin | 1100010010110100111… |
… | …0100110100010110001 |
3 | 202012011202000110120021 |
4 | 3010231032212202301 |
5 | 11430030310400423 |
6 | 241010214243441 |
7 | 21155015036035 |
oct | 3045516464261 |
9 | 665152013507 |
10 | 211212200113 |
11 | 81635865092 |
12 | 34b26656581 |
13 | 16bc01b2c05 |
14 | a31922c1c5 |
15 | 576297c95d |
hex | 312d3a68b1 |
211212200113 has 2 divisors, whose sum is σ = 211212200114. Its totient is φ = 211212200112.
The previous prime is 211212200107. The next prime is 211212200123. The reversal of 211212200113 is 311002212112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 184287328369 + 26924871744 = 429287^2 + 164088^2 .
It is a cyclic number.
It is not a de Polignac number, because 211212200113 - 25 = 211212200081 is a prime.
It is a super-2 number, since 2×2112122001132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211212200123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606100056 + 105606100057.
It is an arithmetic number, because the mean of its divisors is an integer number (105606100057).
Almost surely, 2211212200113 is an apocalyptic number.
It is an amenable number.
211212200113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211212200113 is an equidigital number, since it uses as much as digits as its factorization.
211212200113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 211212200113 its reverse (311002212112), we get a palindrome (522214412225).
The spelling of 211212200113 in words is "two hundred eleven billion, two hundred twelve million, two hundred thousand, one hundred thirteen".
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