Base | Representation |
---|---|
bin | 110000000001100010101100… |
… | …111000110011101101101101 |
3 | 1000200211200122020012121120100 |
4 | 300001202230320303231231 |
5 | 210141000102323234013 |
6 | 2025113314551341313 |
7 | 62326402342464012 |
oct | 6001425470635555 |
9 | 1020750566177510 |
10 | 211212212321133 |
11 | 61331661623041 |
12 | 1b832412681839 |
13 | 90b12c2b4610a |
14 | 3a22a23167709 |
15 | 19641aadcd473 |
hex | c018ace33b6d |
211212212321133 has 24 divisors (see below), whose sum is σ = 310733049669120. Its totient is φ = 138210667529760.
The previous prime is 211212212321083. The next prime is 211212212321147. The reversal of 211212212321133 is 331123212212112.
211212212321133 is a `hidden beast` number, since 2 + 1 + 121 + 2 + 212 + 321 + 1 + 3 + 3 = 666.
It is not a de Polignac number, because 211212212321133 - 26 = 211212212321069 is a prime.
It is a super-2 number, since 2×2112122123211332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211212212321097 and 211212212321106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211212212321833) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 401325441 + ... + 401851382.
It is an arithmetic number, because the mean of its divisors is an integer number (12947210402880).
Almost surely, 2211212212321133 is an apocalyptic number.
It is an amenable number.
211212212321133 is a deficient number, since it is larger than the sum of its proper divisors (99520837347987).
211212212321133 is a wasteful number, since it uses less digits than its factorization.
211212212321133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 803177369 (or 803177366 counting only the distinct ones).
The product of its digits is 1728, while the sum is 27.
Adding to 211212212321133 its reverse (331123212212112), we get a palindrome (542335424533245).
The spelling of 211212212321133 in words is "two hundred eleven trillion, two hundred twelve billion, two hundred twelve million, three hundred twenty-one thousand, one hundred thirty-three".
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