Base | Representation |
---|---|
bin | 10011101010111011… |
… | …011010001001001011 |
3 | 2000111222110210012011 |
4 | 103222323122021023 |
5 | 321224023430212 |
6 | 13411503000351 |
7 | 1345256120035 |
oct | 235273321113 |
9 | 60458423164 |
10 | 21121311307 |
11 | 8a5947a888 |
12 | 41155990b7 |
13 | 1cb7aaa855 |
14 | 10451b0c55 |
15 | 8394114a7 |
hex | 4eaeda24b |
21121311307 has 2 divisors, whose sum is σ = 21121311308. Its totient is φ = 21121311306.
The previous prime is 21121311191. The next prime is 21121311359. The reversal of 21121311307 is 70311312112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21121311307 - 215 = 21121278539 is a prime.
It is a super-2 number, since 2×211213113072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21121312307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560655653 + 10560655654.
It is an arithmetic number, because the mean of its divisors is an integer number (10560655654).
Almost surely, 221121311307 is an apocalyptic number.
21121311307 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121311307 is an equidigital number, since it uses as much as digits as its factorization.
21121311307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 21121311307 its reverse (70311312112), we get a palindrome (91432623419).
The spelling of 21121311307 in words is "twenty-one billion, one hundred twenty-one million, three hundred eleven thousand, three hundred seven".
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