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21121311307 is a prime number
BaseRepresentation
bin10011101010111011…
…011010001001001011
32000111222110210012011
4103222323122021023
5321224023430212
613411503000351
71345256120035
oct235273321113
960458423164
1021121311307
118a5947a888
1241155990b7
131cb7aaa855
1410451b0c55
158394114a7
hex4eaeda24b

21121311307 has 2 divisors, whose sum is σ = 21121311308. Its totient is φ = 21121311306.

The previous prime is 21121311191. The next prime is 21121311359. The reversal of 21121311307 is 70311312112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21121311307 - 215 = 21121278539 is a prime.

It is a super-2 number, since 2×211213113072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21121312307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560655653 + 10560655654.

It is an arithmetic number, because the mean of its divisors is an integer number (10560655654).

Almost surely, 221121311307 is an apocalyptic number.

21121311307 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121311307 is an equidigital number, since it uses as much as digits as its factorization.

21121311307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 21121311307 its reverse (70311312112), we get a palindrome (91432623419).

The spelling of 21121311307 in words is "twenty-one billion, one hundred twenty-one million, three hundred eleven thousand, three hundred seven".