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2112131403002 = 21799162685683
BaseRepresentation
bin11110101111000100110…
…101111000110011111010
321110220210001212022121002
4132233010311320303322
5234101121114344002
64254144430045002
7305411404463315
oct36570465706372
97426701768532
102112131403002
11744828128585
122a1418649762
131242334c588a
1474328b7597c
1539e1c292002
hex1ebc4d78cfa

2112131403002 has 16 divisors (see below), whose sum is σ = 3357946720512. Its totient is φ = 992941202880.

The previous prime is 2112131402999. The next prime is 2112131403007. The reversal of 2112131403002 is 2003041312112.

It is a super-4 number, since 4×21121314030024 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (2112131403007) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31309148 + ... + 31376535.

It is an arithmetic number, because the mean of its divisors is an integer number (209871670032).

Almost surely, 22112131403002 is an apocalyptic number.

2112131403002 is a deficient number, since it is larger than the sum of its proper divisors (1245815317510).

2112131403002 is a wasteful number, since it uses less digits than its factorization.

2112131403002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62686693.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2112131403002 its reverse (2003041312112), we get a palindrome (4115172715114).

The spelling of 2112131403002 in words is "two trillion, one hundred twelve billion, one hundred thirty-one million, four hundred three thousand, two".

Divisors: 1 2 17 34 991 1982 16847 33694 62685683 125371366 1065656611 2131313222 62121511853 124243023706 1056065701501 2112131403002